AP EAMCET · PHYSICS · Mechanical Properties of Fluids
In a hydraulic lift, if the radius of the smaller piston is 5 cm, and the radius of the larger piston is 50 cm, then the weight that the larger piston can support when a force of 250 N is applied to the smaller piston is
- A 50 kN
- B 100 kN
- C 40 kN
- D 25 kN
Answer & Solution
Correct Answer
(D) 25 kN
Step-by-step Solution
Detailed explanation
\(F_2 = F_1 \left(\frac{r_2}{r_1}\right)^2\) \(F_2 = 250 \text{ N} \left(\frac{50 \text{ cm}}{5 \text{ cm}}\right)^2 = 250 \text{ N} (10)^2\) \(F_2 = 25000 \text{ N} = 25 \text{ kN}\)
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