AP EAMCET · PHYSICS · Electrostatics
Two concentric spherical surfaces \(P_1\) and \(P_2\) enclose charges \(\frac{Q}{2}\) and \(4 Q\) as shown in the figure. If \(\phi_1\) and \(\phi_2\) are the electric fluxes linked with the surfaces \(P_1\) and \(P_2\) respectively then
- A \(\phi_2=9 \phi_1\)
- B \(\phi_1=9 \phi_2\)
- C \(\phi_2=2 \phi_1\)
- D \(\phi_1=2 \phi_2\)
Answer & Solution
Correct Answer
(A) \(\phi_2=9 \phi_1\)
Step-by-step Solution
Detailed explanation
As, flux linked with a surface \(\phi=\frac{\mathrm{Q}_{\text {enclosed }}}{\varepsilon_0}\) So flux linked with surfaces \(P_1\) and \(P_2\) are \(\phi_1=\frac{q}{2 \varepsilon_0}\) and \(\quad \phi_2=\frac{q Q}{2 \varepsilon_0}=9\left(\frac{Q}{2 \varepsilon_0}\right)\) or…
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