AP EAMCET · PHYSICS · Motion In Two Dimensions
A ball is thrown upward from the top of a building at an angle of \(30^{\circ}\) to the horizontal and with an initial speed of \(20 \mathrm{~ms}^{-1}\). If the ball strikes the ground after \(3 \mathrm{~s}\). then the height of the building is
(acceleration due to gravity \(=10 \mathrm{~ms}^{-1}\) )
- A \(10 \mathrm{~m}\)
- B \(15 \mathrm{~m}\)
- C \(20 \mathrm{~m}\)
- D \(25 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(15 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given situation is shown below Here we are considering only vertical motion of ball. Given, initial vertical velocity of ball \[ \begin{aligned} u_y & =u \sin \theta=20 \times \sin 30^{\circ} \\ & =20 \times \frac{1}{2}=10 \mathrm{~m} / \mathrm{s} \end{aligned} \] Vertical…
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