AP EAMCET · Chemistry · Some Basic Concepts of Chemistry
\(20 \mathrm{~mL}\) of \(0.1 \mathrm{M} \mathrm{HCl}\) is added to the \(30 \mathrm{~mL}\) of \(0.1 \mathrm{M}\) \(\mathrm{NaOH}\). To this solution extra \(50 \mathrm{~mL}\) of water was added. What is the molarity of the final solution formed?
- A \(0.1 \mathrm{M}\)
- B \(0.01 \mathrm{M}\)
- C \(0.5 \mathrm{M}\)
- D \(0.05 \mathrm{M}\)
Answer & Solution
Correct Answer
(B) \(0.01 \mathrm{M}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n}_{\mathrm{HCl}}=0.1 \mathrm{M} \times 0.02 \mathrm{~L}=0.002 \mathrm{~mol}\) \(\mathrm{n}_{\mathrm{NaOH}}=0.1 \mathrm{M} \times 0.03 \mathrm{~L}=0.003 \mathrm{~mol}\) Number of moles of \(\mathrm{NaOH}\) remaining after neutralization.…
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