AP EAMCET · Maths · Circle
The line \(x+y=k\) meets the curve \(x^2+y^2-2 x-4 y+2=0\) at two points \(\mathrm{A}\) and \(\mathrm{B}\). If \(O\) is the origin and \(\angle \mathrm{AOB}=90^{\circ}\), then the value of \(k(k>1)\) is
- A 5
- B 4
- C 3
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
Eqn. of circle is \(x^2+y^2-2 x-4 y+2=0\) ...(i) Homogenising eqn. (i), we get \(x^2+y^2-2 x \times 1-4 y \times 1+2 \times(1)^2=0\)…
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