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AP EAMCET · PHYSICS · Electromagnetic Induction

A long solenoid having 100 turns per \(\mathrm{cm}\) carries a current of \(\frac{4}{\pi}\) A. At the centre of it is placed a coil of 200 turns of cross-sectional area \(25 \mathrm{~cm}^2\) having its axis parallel to the field produced by the solenoid. When the direction of the current in the solenoid is reversed with in \(0.04 \mathrm{~s}\), the induced emf in the coil is

  1. A \(0.2 \mathrm{~V}\)
  2. B \(0.4 \mathrm{~V}\)
  3. C \(0.002 \mathrm{~V}\)
  4. D \(0.016 \mathrm{~V}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0.4 \mathrm{~V}\)

Step-by-step Solution

Detailed explanation

Due to solenoid a magnetic field exists around coil placed at centre Magnetic field intensity produced by solenoid, \(B=\mu_0 n I\) Flux linked with coil is \(\phi_B=N . B \cdot A\) Where, \(N=\) Number of turns in coil \(A=\) Area of coil As current in solenoid is reversed,…
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