AP EAMCET · PHYSICS · Alternating Current
A series LCR circuit is shown in the figure. Where the inductance of 10 H , capacitance \(40 \mu \mathrm{~F}\) and resistance 60 \(\Omega\) are connected to a variable frequency 240 V source. The current at resonating frequency is
- A 4A
- B 2A
- C 5.4A
- D 5.8A
Answer & Solution
Correct Answer
(A) 4A
Step-by-step Solution
Detailed explanation
In LCR series circuit, \(\mathrm{L}=10 \mathrm{H}, \mathrm{C}=40 \mu \mathrm{~F}, \mathrm{R}=60 \Omega, \mathrm{~V}=240 \mathrm{v}\) At resonance, \(Z=R=60 \Omega\) \(\therefore\) Current, \(I=\frac{V}{Z}=\frac{240}{60}=4 \mathrm{~A}\)
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