AP EAMCET · PHYSICS · Electromagnetic Induction
To measured a magnetic field between the magnetic poles of a loud speaker, a small coil having 30 turns and \(2.5 \mathrm{~cm}^2\) area is placed perpendicular to the field and removed immediately. If the total charge flown through the coil is \(75 \times 10^{-3} \mathrm{C}\) and the total resistance of wire and galvanometer is \(0.3 \Omega\), then the magnitude of the magnetic field is
- A \(0.03 \mathrm{~T}\)
- B \(0.3 \mathrm{~T}\)
- C \(3 \mathrm{~T}\)
- D \(3 \times 10^2 \mathrm{~T}\)
Answer & Solution
Correct Answer
(B) \(0.3 \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
Given, number of turns in the coil, \(N=30\) turns area of the coil, \(A=2.5 \mathrm{~cm}^2=2.5 \times 10^{-4} \mathrm{~m}^2\) total charge flowing through the coil, \(Q_{\text {Net }}=7.5 \times 10^{-3} \mathrm{C}\) and total resistance of wire and galvanometer,…
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