AP EAMCET · PHYSICS · Current Electricity
In the given circuit, current \(I\) is independent of the resistance \(R_6\). Then
- A \(R_1 R_2 R_5=R_3 R_4 R_6\)
- B \(\frac{1}{R_5}+\frac{1}{R_6}=\frac{1}{R_1+R_2}+\frac{1}{R_3+R_4}\)
- C \(R_1 R_4=R_2 R_3\)
- D \(R_1 R_3=R_2 R_4\)
Answer & Solution
Correct Answer
(C) \(R_1 R_4=R_2 R_3\)
Step-by-step Solution
Detailed explanation
If resistance \(R_1, R_2, R_3, R_4\) and \(R_6\) from Wheatstone bridge, then current will independent of resistance \(R_6\). For this, \(\frac{R_1}{R_2}=\frac{R_3}{R_4} \Rightarrow R_1 R_4=R_2 R_3\)
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