AP EAMCET · PHYSICS · Electrostatics
Three charges \(+5 q, Q\) and \(-2 q\) are kept along a straight line in the same order such that, \(+5 q\) and \(-2 q\) charges are at a distance of \(\frac{2 r}{3}\) and \(\frac{r}{3}\) from the charge \(Q\) respectively. If the net force on the charge \(-2 q\) is zero, then \(Q\) is
- A \(+\frac{5}{9} q\)
- B \(-\frac{5}{9} q\)
- C \(3 q\)
- D \(-3 q\)
Answer & Solution
Correct Answer
(A) \(+\frac{5}{9} q\)
Step-by-step Solution
Detailed explanation
The given situation is shown below. Since, net force on charge \((-2 q)\) is zero, Therefore, charge \(Q\) must be positive so that there are two opposing forces on charge \(-2 q\). Now, \(\quad F_{\text {net }}=0\) i.e. \(\quad F(5 q,-2 q)=F(Q,-2 q)\)…
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