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AP EAMCET · Maths · Hyperbola

The asymptotes of the hyperbola x2a2-y2b2=1, with any tangent to the hyperbola form a triangle whose area is a2tanα. Then its eccentricity equals

  1. A secα
  2. B cosecα
  3. C sec2α
  4. D cosec2α
Verified Solution

Answer & Solution

Correct Answer

(A) secα

Step-by-step Solution

Detailed explanation

Given hyperbola x2a2-y2b2=1 Asymptotes of hyperbola are xa+yb=0...I , xa-yb=0...II Tangent at x1, y1 is xx1a2-yy1b2=1....III We know that area formed by a triangle with asymptotes and any tangent is equal to ab. ⇒ab = a2 tan α…