AP EAMCET · PHYSICS · Dual Nature of Matter
In a photoelectric experiment, a graph is drawn with stopping potential along \(\mathrm{Y}\)-axis and the frequency of the incident light along \(\mathrm{X}\)-axis. If the graph is a straight line which makes an angle \(\theta\) with Y-axis, then \(\tan \theta=\) (h-planck's constant, e-charge of electron)
- A \(\frac{\mathrm{h}}{\mathrm{e}}\)
- B \(\frac{\mathrm{e}}{\mathrm{h}}\)
- C \(\sqrt{\frac{\mathrm{h}}{\mathrm{e}}}\)
- D \(\sqrt{\frac{\mathrm{e}}{\mathrm{h}}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mathrm{h}}{\mathrm{e}}\)
Step-by-step Solution
Detailed explanation
From the photoelectric equation \(\begin{aligned} & \mathrm{eV}_{\mathrm{s}}=\mathrm{hv}-\phi \\ & \mathrm{V}_{\mathrm{s}}=\frac{\mathrm{hv}}{\mathrm{e}}-\frac{\phi}{\mathrm{e}}\end{aligned}\) By compairing above equation with \(\mathrm{y}=\mathrm{mx}+\mathrm{c}\) slope…
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