AP EAMCET · PHYSICS · Electrostatics
When a \(5 \mathrm{C}\) charge is kept in a uniform electric field, a force of \(5000 \mathrm{~N}\) acts on it. Find the potential difference between two points in that field, separated by a distance of \(1 \mathrm{~cm}\).
- A \(10 \mathrm{~V}\)
- B \(250 \mathrm{~V}\)
- C ) \(1000 \mathrm{~V}\)
- D \(2500 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(10 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Charge, \(q=5 \mathrm{C}\) Force, \[ \begin{aligned} & F=5000 \mathrm{~N} \\ & d=1 \mathrm{~cm}=10^{-2} \mathrm{~m} \end{aligned} \] \(\therefore\) Potential difference between the given points,…
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