AP EAMCET · PHYSICS · Work Power Energy
The work done in moving a body of mass \(2 \mathrm{~kg}\) to a height of \(4 \mathrm{~m}\) from the surface of the earth is
(Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(10 \mathrm{~J}\)
- B \(20 \mathrm{~J}\)
- C \(40 \mathrm{~J}\)
- D \(80 \mathrm{~J}\)
Answer & Solution
Correct Answer
(D) \(80 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Mass of body, M=2 kg Height, \(\mathrm{H}=4 \mathrm{~m}\) work done to lift a body = potential energy of body \[ \begin{aligned} & \therefore W=m g h=2 \times 10 \times 4 \\ & W=80 \mathrm{~J} \end{aligned} \]
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