AP EAMCET · PHYSICS · Motion In Two Dimensions
A projectile is given an initial velocity of \((\hat{\mathbf{i}}+2 \hat{\mathbf{j}}) \mathrm{ms}^{-1}\). The equation of its path is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
- A \(y=2 x-5 x^2\)
- B \(y=x-5 x^2\)
- C \(4 y=2 x-5 x^2\)
- D \(y=2 x-25 x^2\)
Answer & Solution
Correct Answer
(A) \(y=2 x-5 x^2\)
Step-by-step Solution
Detailed explanation
Velocity of particle is \((\hat{\mathbf{i}}+2 \hat{\mathbf{j}}) \mathrm{ms}^{-1}\) initially. So, \(\quad u_x=1 \mathrm{~ms}^{-1}\) and \(u_y=2 \mathrm{~ms}^{-1}\) Also, \(\quad a_x=0\) and \(a_y=-10 \mathrm{~ms}^{-2}\) In time \(t\), Horizontal distance covered by projectile is…
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