AP EAMCET · PHYSICS · Gravitation
The value of acceleration due to gravity \(g\) is maximum at
- A poles
- B centre
- C equator
- D surface of earth
Answer & Solution
Correct Answer
(A) poles
Step-by-step Solution
Detailed explanation
The acceleration due to gravity on the surface of earth is given as \[ g^{\prime}=g-\omega^2 R_e \cos ^2 \lambda \] where, \(\lambda\) is the angle of lattitude. At poles, \(\lambda=90^{\circ}\) \(\therefore \quad \cos 90^{\circ}=0\) From Eq. (i), \[ g^{\prime}=g \] Hence, at…
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