AP EAMCET · Chemistry · Structure of Atom
The ratio of lowest energy in terms of wave numbers of Balmer and Lyman series of lines of atomic spectrum of hydrogen is
- A 5 : 27
- B 27 : 5
- C 20 : 27
- D 27 : 2
Answer & Solution
Correct Answer
(A) 5 : 27
Step-by-step Solution
Detailed explanation
(a) \(\because\) Wave number \((v)=R \cdot Z^2\left\lceil\frac{1}{n_{\mathrm{L}^2}}-\frac{1}{n_{\mathrm{H}^2}}\right\rfloor\) Wave number for lowest energy for Balmer series \(\left(n_{\mathrm{L}}=2, n_{\mathrm{H}}=3\right)\)…
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