AP EAMCET · PHYSICS · Motion In Two Dimensions
A particle is projected with velocity \(2 \sqrt{g h}\), so that it just flies over two walls of equal height \(h\) and \(2 h\) distance apart from each other. Find the time for which the particle flies between the walls.
- A \(\sqrt{\frac{4 h}{g}}\)
- B \(\sqrt{\frac{h}{g}}\)
- C \(\sqrt{\frac{4 g}{h}}\)
- D \(\sqrt{\frac{g}{h}}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{\frac{4 h}{g}}\)
Step-by-step Solution
Detailed explanation
Velocity of projection, \[ \begin{aligned} v & =2 \sqrt{g h} \\ \therefore \quad v_x & =v \cos \theta=2 \sqrt{g h} \cos \theta \end{aligned} \] \(\therefore\) Time taken by the projectile to cover interwall distance,…
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