AP EAMCET · PHYSICS · Kinetic Theory of Gases
The rms velocity of a gas molecule of mass ' \(m\) ' at a given temperature is proportional to
- A \(\mathrm{m}^{\circ}\)
- B m
- C \(\sqrt{m}\)
- D \(\frac{1}{\sqrt{m}}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{\sqrt{m}}\)
Step-by-step Solution
Detailed explanation
The rms velocity of a gas molecule of mass \(m\) is \(\mathrm{v}_{\mathrm{rms}}=\sqrt{\frac{3 \mathrm{KT}}{\mathrm{m}}} \Rightarrow \mathrm{v}_{\mathrm{rms}} \propto \frac{1}{\sqrt{\mathrm{~m}}}\)
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