AP EAMCET · Maths · Application of Derivatives
If a man of height 1.8 mt . is walking away from the foot of a light pole of height 6 mt . with a speed of 7 km per hour on a straight horizontal road opposite to the pole, then the rate of change of the length of his shadow is (in kmph)
- A \(7\)
- B \(5\)
- C \(3\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
Let OA be the light pole, GF be the man standing at G after time t . In \(\triangle \mathrm{AEF}, \tan \theta=\frac{4.2}{x}\) In \(\triangle \mathrm{AOB}, \tan \theta=\frac{6}{x+y}\) \(\Rightarrow \frac{4.2}{x}=\frac{6}{x+y} \Rightarrow 1.8 x=4.2 y\) Differentiating w.r.t. t…
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