AP EAMCET · PHYSICS · Work Power Energy
A small disc is on the top of a smooth hemisphere of radius ' R '. The smallest horizontal velocity ' \(V\) ' that should be imparted to the disc so that disc leaves the hemisphere surface without sliding down is (there is no friction)
- A \(V=\sqrt{g^2 R}\)
- B \(V=\sqrt{2 g R}\)
- C \(V=\sqrt{g R}\)
- D \(V=\sqrt{g / R}\)
Answer & Solution
Correct Answer
(C) \(V=\sqrt{g R}\)
Step-by-step Solution
Detailed explanation
At the top of hemisphere, \(\mathrm{mg}-\mathrm{N}=\frac{\mathrm{mv}^2}{\mathrm{R}}\) For the disc leaves the hemisphere, \(\mathrm{N}=0 \quad \therefore \mathrm{mg}=\frac{\mathrm{mv}^2}{\mathrm{R}} \Rightarrow \mathrm{v}=\sqrt{\mathrm{gR}}\)
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