AP EAMCET · PHYSICS · Atomic Physics
The ratio of the time periods of the revolution of the electrons in the second and third excited states of hydrogen atom is
- A \(9: 16\)
- B \(27: 64\)
- C \(4: 9\)
- D \(8: 27\)
Answer & Solution
Correct Answer
(B) \(27: 64\)
Step-by-step Solution
Detailed explanation
\(T \propto n^3\) \(n_1 = 3\) (second excited state) \(n_2 = 4\) (third excited state) \(\frac{T_2}{T_3} = \frac{n_1^3}{n_2^3} = \frac{3^3}{4^3} = \frac{27}{64}\)
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