AP EAMCET · Maths · Pair of Lines
The equations \(x-y=4\) and \(x^2+4 x y+y^2=0\) represent the sides of a/an
- A Isosceles Triangle
- B Right Angled Triangle
- C Equilateral Triangle
- D Scalene Triangle
Answer & Solution
Correct Answer
(C) Equilateral Triangle
Step-by-step Solution
Detailed explanation
Slopes from \(x^2+4xy+y^2=0\): Let \(m=\frac{y}{x}\). \(m^2+4m+1=0 \implies m_{1,2} = \frac{-4 \pm \sqrt{16-4}}{2} = -2 \pm \sqrt{3}\). Slope from \(x-y=4\): \(y=x-4 \implies m_3 = 1\). Angle between lines with slopes \(m_1\) and \(m_2\):…
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