AP EAMCET · PHYSICS · Magnetic Properties of Matter
In the magnetic meridian of a certain place, the vertical component of the earth's magnetic field is \(0.3464 \mathrm{G}\) and the dip angle is \(30^{\circ}\). The horizontal component of the earth's magnetic field at this location is
- A 0.4 G
- B 0.6 G
- C 0.7 G
- D 0.8 G
Answer & Solution
Correct Answer
(B) 0.6 G
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \tan \delta=\frac{B_V}{B_H} \Rightarrow B_H=\frac{B_V}{\tan \delta}=\frac{0.3464}{(1 / \sqrt{3})} \\ & =0.3464 \times 1.73=0.6 \mathrm{G}\end{aligned}\)
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