AP EAMCET · PHYSICS · Atomic Physics
The radius of the nucleus of an atom whose mass number is 125 is
- A \(1 \times 10^{-15} \mathrm{~m}\)
- B \(6 \times 10^{-15} \mathrm{~m}\)
- C \(10 \times 10^{-15} \mathrm{~m}\)
- D \(16 \times 10^{-15} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(6 \times 10^{-15} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & R=R_0 A^{1 / 3} \\ & =1.2 \times 10^{-15} \times(125)^{1 / 3} \\ & =1.2 \times 10^{-15} \times(5)^{3 \times \frac{1}{3}} \\ & =6 \times 10^{-15} \mathrm{~m} .\end{aligned}\)
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