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AP EAMCET · Maths · Properties of Triangles

In a \(\triangle A B C\), if \(\angle A=90^{\circ}\), then \(\cos ^{-1}\left(\frac{R}{r_2+r_3}\right)\) is equal to

  1. A \(90^{\circ}\)
  2. B \(30^{\circ}\)
  3. C \(60^{\circ}\)
  4. D \(45^{\circ}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(60^{\circ}\)

Step-by-step Solution

Detailed explanation

Given, \(\angle \mathrm{A}=90^{\circ}\) In \(\triangle A B C\), we know that…