AP EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C\), if \(\angle A=90^{\circ}\), then \(\cos ^{-1}\left(\frac{R}{r_2+r_3}\right)\) is equal to
- A \(90^{\circ}\)
- B \(30^{\circ}\)
- C \(60^{\circ}\)
- D \(45^{\circ}\)
Answer & Solution
Correct Answer
(C) \(60^{\circ}\)
Step-by-step Solution
Detailed explanation
Given, \(\angle \mathrm{A}=90^{\circ}\) In \(\triangle A B C\), we know that…
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