AP EAMCET · PHYSICS · Thermodynamics
A refrigerator of coefficient of performance 5 that extracts heat from the cooling compartment at the rate of 250 J per cycle is placed in a room. The heat released per cycle to the room by the refrigerator is
- A 250 J
- B 50 J
- C 200 J
- D 300 J
Answer & Solution
Correct Answer
(D) 300 J
Step-by-step Solution
Detailed explanation
\(Q_H = Q_L \left(1 + \frac{1}{COP}\right)\) \(Q_H = 250 \text{ J} \left(1 + \frac{1}{5}\right) = 250 \text{ J} \left(\frac{6}{5}\right) = 300 \text{ J}\)
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