AP EAMCET · PHYSICS · Work Power Energy
The power required for an engine to maintain a constant speed of \(50 \mathrm{~m} \mathrm{~s}^{-1}\) for a train of mass \(3 \times 10^6 \mathrm{~kg}\) on rough rails is
(The coefficient of kinetic friction between the rails and wheels of the train is 0.05 and acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A 75 MW
- B 40 MW
- C 75 kW
- D 65 MW
Answer & Solution
Correct Answer
(A) 75 MW
Step-by-step Solution
Detailed explanation
\(N = mg = (3 \times 10^6 \mathrm{~kg})(10 \mathrm{~m} \mathrm{~s}^{-2}) = 3 \times 10^7 \mathrm{~N}\) \(F_f = \mu_k N = (0.05)(3 \times 10^7 \mathrm{~N}) = 1.5 \times 10^6 \mathrm{~N}\)…
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