AP EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
The correct order of atomic radii of \(\mathrm{B}, \mathrm{Be}, \mathrm{N}\) and \(\mathrm{C}\) is
- A \(\mathrm{Be} < \mathrm{B} < \mathrm{C} < \mathrm{N}\)
- B \(\mathrm{N} < \mathrm{B} < \mathrm{C} < \mathrm{Be}\)
- C \(\mathrm{N} < \mathrm{C} < \mathrm{B} < \mathrm{Be}\)
- D \(\mathrm{Be} < \mathrm{C} < \mathrm{B} < \mathrm{N}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{N} < \mathrm{C} < \mathrm{B} < \mathrm{Be}\)
Step-by-step Solution
Detailed explanation
Atomic radii generally decreases in a period from left to right due to an increase in the effective nuclear charge. Thus, \({ }_7 \mathrm{~N} < { }_6 \mathrm{C} < { }_5 \mathrm{~B} < { }_4 \mathrm{Be}\)
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