AP EAMCET · PHYSICS · Semiconductors
For a common-emitter transistor amplifier, the current gain is 60 . If the emitter current is \(6.6 \mathrm{~mA}\), then its base current is
- A \(6.492 \mathrm{~mA}\)
- B \(0.108 \mathrm{~mA}\)
- C \(4.208 \mathrm{~mA}\)
- D \(0.343 \mathrm{~mA}\)
Answer & Solution
Correct Answer
(B) \(0.108 \mathrm{~mA}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Using } l_{\mathrm{E}}=l_{\mathrm{B}}+l_{\mathrm{C}} \\ & \Rightarrow l_{\mathrm{B}}=l_{\mathrm{E}}-l_{\mathrm{C}} \\ & =6.6 \times 10^{-3}-60 l_{\mathrm{B}} \\ & \Rightarrow \quad l_{\mathrm{B}}+60 l_{\mathrm{B}}=6.6 \times 10^{-3} \\ & \text { or }…
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