AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
The position-time \((x-t)\) graph of a moving body of mass \(2 \mathrm{~kg}\) is shown in the figure. The impulse on the body at \(t=4 \mathrm{~s}\) is
- A \(1.5 \mathrm{~kg}-\mathrm{ms}^{-1}\)
- B \(-1.5 \mathrm{~kg}-\mathrm{ms}^{-1}\)
- C \(1 \mathrm{~kg}-\mathrm{ms}^{-1}\)
- D \(2 \mathrm{~kg}-\mathrm{ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(-1.5 \mathrm{~kg}-\mathrm{ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Here, mass of the body, \(m=2 \mathrm{~kg}\) and time, \[ t=4 \mathrm{~s} \] Impulse \(=p_f-p_i\) where, \(p_i=\) initial momentum, \(p_f=\) final momentum Impulse \(\quad=m v_f-m v_i=m\left(v_f-v_i\right) \quad(\because p=m v)\) As from the graph,…
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