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AP EAMCET · Maths · Circle

If \(x-y+1=0\) meets the circle \(x^2+y^2+y-1=0\) at \(A\) and \(B\), then the equation of the circle with \(A B\) as diameter is

  1. A \(2\left(x^2+y^2\right)+3 x-y+1=0\)
  2. B \(2\left(x^2+y^2\right)+3 x-y+2=0\)
  3. C \(2\left(x^2+y^2\right)+3 x-y+3=0\)
  4. D \(x^2+y^2+3 x-y+4=0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2\left(x^2+y^2\right)+3 x-y+1=0\)

Step-by-step Solution

Detailed explanation

Given that circle, \(S=x^2+y^2+y-1=0\) Line, \(\mathrm{L}: x-y+1=0\) Equation of the circle passing through the intersection of line and circle is given by…