AP EAMCET · Maths · Circle
If \(x-y+1=0\) meets the circle \(x^2+y^2+y-1=0\) at \(A\) and \(B\), then the equation of the circle with \(A B\) as diameter is
- A \(2\left(x^2+y^2\right)+3 x-y+1=0\)
- B \(2\left(x^2+y^2\right)+3 x-y+2=0\)
- C \(2\left(x^2+y^2\right)+3 x-y+3=0\)
- D \(x^2+y^2+3 x-y+4=0\)
Answer & Solution
Correct Answer
(A) \(2\left(x^2+y^2\right)+3 x-y+1=0\)
Step-by-step Solution
Detailed explanation
Given that circle, \(S=x^2+y^2+y-1=0\) Line, \(\mathrm{L}: x-y+1=0\) Equation of the circle passing through the intersection of line and circle is given by…
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