AP EAMCET · PHYSICS · Communication System
The maximum distance between the transmitting and receiving TV towers is \(65 \mathrm{~km}\). If the ratio of the heights of the TV transmitting tower to receiving tower is \(36: 49\), the heights of the transmitting and receiving towers respectively are (radius of earth \(=6400 \mathrm{~km}\))
- A 51.2 m, 80 m
- B 70.3 m, 95.7 m
- C 30 m, 65 m
- D 25 m, 75 m
Answer & Solution
Correct Answer
(B) 70.3 m, 95.7 m
Step-by-step Solution
Detailed explanation
From Eqs. (i) and (ii), we get and \(\begin{aligned} & h_T=70.3 \mathrm{~m} \\ & h_R=95.7 \mathrm{~m} \end{aligned}\)
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