AP EAMCET · PHYSICS · Waves and Sound
The wavelengths of two sound notes in air are \(\frac{40}{195} \mathrm{~m}\) and \(\frac{40}{193} \mathrm{~m}\). Each note produces 9 beats per second separately with a third note of fixed frequency. The velocity of sound in air in \(\mathrm{m} / \mathrm{s}\) is
- A 360
- B 320
- C 300
- D 340
Answer & Solution
Correct Answer
(A) 360
Step-by-step Solution
Detailed explanation
Here, \(\quad v_1=\frac{v}{\left(\frac{40}{195}\right)}\) \(\begin{array}{ll}\text { and } & v_2=\frac{v}{\left(\frac{40}{193}\right)} \\ \Rightarrow & v_1=\frac{v(195)}{40}\end{array}\) and \(\quad v_2=\frac{v(193)}{40}\) According to given condition \(\frac{v}{40}(195)-v=9\)…
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