AP EAMCET · PHYSICS · Electromagnetic Waves
The magnitude of the electric field of a plane electromagnetic wave travelling in free space is \(E\). If \(\mu_0\) and \(\varepsilon_0\) are respectively permeability and permittivity of the free space, then the magnitude of magnetic field of the wave is
- A \(E \mu_0 \varepsilon_0\)
- B \(\frac{E}{\mu_0 \varepsilon_0}\)
- C \(E \sqrt{\mu_0 \varepsilon_0}\)
- D \(\frac{E}{\sqrt{\mu_0 \varepsilon_0}}\)
Answer & Solution
Correct Answer
(C) \(E \sqrt{\mu_0 \varepsilon_0}\)
Step-by-step Solution
Detailed explanation
\(c = \frac{E}{B}\) \(c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}\) \(\frac{E}{B} = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}\) \(B = E \sqrt{\mu_0 \varepsilon_0}\)
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