AP EAMCET · Maths · Continuity and Differentiability
\(\mathrm{f}(\mathrm{x})\) is differentiable on \(\mathbb{R}\) and \(\mathrm{f}^{\prime}(\mathrm{m}) \neq 0, \mathrm{~m} \in \mathbb{R}\).
If \(\lim _{x \rightarrow m} \frac{x f(m)-m f(x)}{x-m}+f^{\prime}(m)=f(m)\), then \(m=\)
- A \(0\)
- B \(-1\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
Let \(f(x)=\frac{1}{3} x^3+2 x\) \(\Rightarrow f^{\prime}(x)=x^2+2 \neq 0 \forall x \in R\) Now, \(\lim _{x \rightarrow m} \frac{x f(m)-m f(x)}{x-m}+f^{\prime}(m)=f(m)\)…
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