AP EAMCET · Chemistry · Structure of Atom
Calculate energy of half mole of photons of a radiation with frequency \(3 \times 10^{12} \mathrm{~Hz}\).
- A \(598.2 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- B \(0.598 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- C \(1.196 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- D \(119.6 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(B) \(0.598 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
Energy of a photon, \(E=h v\), where, \(v=\) frequency \(=3 \times 10^{12} \mathrm{~Hz}\) Therefore, energy \(=6.6 \times 10^{-34} \times 3 \times 10^{12} \mathrm{~Hz}=1.9878 \times 10^{-21} \mathrm{~J}\) 1 mole \(=6.02 \times 10^{23}\) photons, therefore, \(\frac{1}{2}\) mole…
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