AP EAMCET · PHYSICS · Electromagnetic Waves
The magnetic field in a plane electromagnetic wave is given as
\(\mathbf{B}=\left(3 \times 10^{-7} \mathrm{~T}\right) \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{j}\)
The electric field of this wave is given as
- A \(90 \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{i} \mathrm{Vm}^{-1}\)
- B \(90 \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{k} \mathrm{Vm}^{-1}\)
- C \(45 \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{i} \mathrm{Vm}^{-1}\)
- D \(45 \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{k} \mathrm{Vm}^{-1}\)
Answer & Solution
Correct Answer
(B) \(90 \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \hat{k} \mathrm{Vm}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, Magnetic field in a plane EM wave, \(B=\left(3 \times 10^{-7} \mathrm{~T}\right) \sin \left(3 \times 10^4 x+9 \times 10^{12} t\right) \mathrm{T}\) Here, \(B_0=3 \times 10^{-7} \mathrm{~T}\) Amplitude of electric field,…
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