AP EAMCET · PHYSICS · Ray Optics
The radius of curvature of a convex lens is \(40 \mathrm{~cm}\), for each surface. Its refractive index is 1.5 . Its focal length is
- A \(40 \mathrm{~cm}\)
- B \(20 \mathrm{~cm}\)
- C \(80 \mathrm{~cm}\)
- D \(30 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(A) \(40 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
From the formula \(\begin{aligned} & \frac{1}{\mathrm{f}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right) \\ & \frac{1}{\mathrm{f}}=(1.5-1)\left(\frac{2}{40}\right)=\frac{1}{40}\end{aligned}\) focal length, \(f=40 \mathrm{~cm}\)
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