AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
Two particles of masses \(5 \mathrm{~g}\) and \(3 \mathrm{~g}\) are separated by a distance of \(40 \mathrm{~cm}\). The centre of mass of the system of these two particles
- A lies at a distance of \(15 \mathrm{~cm}\) from \(5 \mathrm{~g}\) particle
- B lies at a distance of \(25 \mathrm{~cm}\) from \(5 \mathrm{~g}\) particle
- C lies at a distance of \(10 \mathrm{~cm}\) from \(3 \mathrm{~g}\) particle
- D lies at the mid point of the line joining the two particles
Answer & Solution
Correct Answer
(B) lies at a distance of \(25 \mathrm{~cm}\) from \(5 \mathrm{~g}\) particle
Step-by-step Solution
Detailed explanation
Suppose centre of mass is \(\mathrm{x} \mathrm{cm}\) away from \(3 \mathrm{~g}\) and assuming that \(3 \mathrm{~g}\) is at \(\mathrm{x}=0\)…
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