AP EAMCET · PHYSICS · Capacitance
The given circuit shows two capacitors connected to a battery. After the capacitors are completely charged, the battery is removed and the capacitors are connected with plates of opposite polarity together. Then the charge on \(2 \mathrm{C}\) and the energy lost in the process are respectively

- A \(0, \frac{2 \mathrm{CE}^2}{3}\)
- B \(0, \frac{\mathrm{CE}^2}{3}\)
- C \(\mathrm{Q}, \frac{2 \mathrm{CE}^2}{3}\)
- D \(2 \mathrm{Q}, \frac{\mathrm{CE}^2}{3}\)
Answer & Solution
Correct Answer
(B) \(0, \frac{\mathrm{CE}^2}{3}\)
Step-by-step Solution
Detailed explanation
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