AP EAMCET · PHYSICS · Current Electricity
Two cells \(P\) and \(Q\) each of emf \(2.16 \mathrm{~V}\) are connected in series with a resistor of \(19.6 \Omega\). An ideal voltmeter reads \(2 \mathrm{~V}\), when connected across the cell \(P\) and \(1.92 \mathrm{~V}\) when connected across the cell \(Q\). The ratio of the internal resistances of the cell \(P\) and \(Q\) is
- A 1 : 2
- B 2 : 3
- C 3 : 4
- D 1 : 3
Answer & Solution
Correct Answer
(B) 2 : 3
Step-by-step Solution
Detailed explanation
Emf of each cell \(=2.16 \mathrm{~V}\) Emf of circuit \(=4.32 \mathrm{~V}\) Current in circuit, \( I=\frac{4.32}{r_1+r_2+19.6} \) Now, using \(V=E-I \cdot r\) for both cells, we have For \(P, 2=2.16-\frac{4.32 r_1}{r_1+r_2+19.6}\) and For…
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