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AP EAMCET · PHYSICS · Current Electricity

Two cells \(P\) and \(Q\) each of emf \(2.16 \mathrm{~V}\) are connected in series with a resistor of \(19.6 \Omega\). An ideal voltmeter reads \(2 \mathrm{~V}\), when connected across the cell \(P\) and \(1.92 \mathrm{~V}\) when connected across the cell \(Q\). The ratio of the internal resistances of the cell \(P\) and \(Q\) is

  1. A 1 : 2
  2. B 2 : 3
  3. C 3 : 4
  4. D 1 : 3
Verified Solution

Answer & Solution

Correct Answer

(B) 2 : 3

Step-by-step Solution

Detailed explanation

Emf of each cell \(=2.16 \mathrm{~V}\) Emf of circuit \(=4.32 \mathrm{~V}\) Current in circuit, \( I=\frac{4.32}{r_1+r_2+19.6} \) Now, using \(V=E-I \cdot r\) for both cells, we have For \(P, 2=2.16-\frac{4.32 r_1}{r_1+r_2+19.6}\) and For…
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