AP EAMCET · PHYSICS · Thermal Properties of Matter
Water of mass m at \(30^{\circ} \mathrm{C}\) is mixed with 5 g of ice at \(-20^{\circ} \mathrm{C}\). If the resultant temperature of the mixture is \(6^{\circ} \mathrm{C}\), then the value of \(m\) is (specific heat capacity of ice \(\mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\) and latent heat of fusion of ice \(=80 \mathrm{cal} \mathrm{g}^{-1}\) )
- A 48 g
- B 20 g
- C 24 g
- D 40 g
Answer & Solution
Correct Answer
(B) 20 g
Step-by-step Solution
Detailed explanation
By principle of calorimetry,…
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