AP EAMCET · PHYSICS · Work Power Energy
A circular well of diameter 2 m has water upto the ground level. If the bottom of the well is at a depth of 14 m, the time taken in seconds to empty the well using a 1.4 kW motor is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A \(1860\)
- B \(2200\)
- C \(2660\)
- D \(3300\)
Answer & Solution
Correct Answer
(B) \(2200\)
Step-by-step Solution
Detailed explanation
\(W = \rho \pi r^2 g \frac{h^2}{2}\) \(W = 1000 \times \pi \times (1)^2 \times 10 \times \frac{(14)^2}{2} = 980000\pi \text{ J}\) \(t = \frac{W}{P}\) \(t = \frac{980000\pi}{1400} = 700\pi \approx 2199.1 \approx 2200 \text{ s}\)
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