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AP EAMCET · Maths · Trigonometric Ratios & Identities

If \(\sin A+\sin B=\frac{1}{2}\) and \(\cos A+\cos B=1\), then \(\sin \left(\frac{A-B}{2}\right)\) equals

  1. A \(\pm \frac{\sqrt{13}}{4}\)
  2. B \(\pm \frac{\sqrt{11}}{4}\)
  3. C \(\pm \frac{\sqrt{7}}{4}\)
  4. D \(\pm \frac{\sqrt{17}}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\pm \frac{\sqrt{11}}{4}\)

Step-by-step Solution

Detailed explanation

Given \(\sin A+\sin B=\frac{1}{2}\) and \(\cos A+\cos B=1\), on square and add the given relations, we get \[ \begin{array}{ll} 2+2(\cos A \cos B+\sin A \sin B)=\frac{1}{4}+1 \\ \Rightarrow & 2 \cos (A-B)=-\frac{3}{4} \\ \Rightarrow & \cos (A-B)=-\frac{3}{8} \end{array} \]…