AP EAMCET · PHYSICS · Ray Optics
The focal length of a convex lens is \(f\). An object is placed at a distance \(x\) from its first focal point. The ratio of the size of the real image to that of the object is
- A \(\frac{f}{x^2}\)
- B \(\frac{x^2}{f}\)
- C \(\frac{f}{x}\)
- D \(\frac{x}{f}\)
Answer & Solution
Correct Answer
(C) \(\frac{f}{x}\)
Step-by-step Solution
Detailed explanation
Given that, focal length of convex lens \(=f\) Distance of object from lst focus point \(=x\) Now, object distance, \(u=-(f+x)\) We know that, ratio of size of real image to that of object = magnification which is given by \(m=\frac{v}{u}=\frac{f}{f+u}\)…
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