AP EAMCET · PHYSICS · Dual Nature of Matter

Radiation of wavelength $300 nm$ and intensity $100 W m^{- 2}$ falls on the surface of a photosensitive material. If $2 %$ of the incident photons produce photo electron, the number of photoelectrons emitted from an area of $2 {cm}^{2}$ of the surface is nearly

A $15 \times 10^{11}$
B $6.04 \times 10^{14}$
C $1.5 \times 10^{12}$
D $60.4 \times 10^{15}$

Verified Solution

Answer & Solution

Correct Answer

(B) $6.04 \times 10^{14}$

Step-by-step Solution

Detailed explanation

Power of radiation is expressed as, Power=Nhcλ Here, N is the number of photons per unit time per unit area. ⇒P=Nhcλ⇒N=Pλhc=100 W m-2×300×10-9 m6.6×10-34 J s×3×108 m s-1=1.51×1020…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Radiation of wavelength 300 nm and intensity 100 W m-2 falls on the surface of a photosensitive material. If 2% of the incident photons produce photo electron, the number of photoelectrons emitted from an area of 2 cm2 of the surface is nearly

Step-by-step Solution

Radiation of wavelength $300 nm$ and intensity $100 W m^{- 2}$ falls on the surface of a photosensitive material. If $2 %$ of the incident photons produce photo electron, the number of photoelectrons emitted from an area of $2 {cm}^{2}$ of the surface is nearly