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AP EAMCET · Maths · Probability

Three students A, B and C are running a race. A and B have the same probability of winning and each is twice likely to win as C. Then, the
probability that B or C wins is equal to (assuming there are no ties)

  1. A \(\frac{2}{5}\)
  2. B \(\frac{3}{5}\)
  3. C \(\frac{3}{7}\)
  4. D \(\frac{2}{7}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{3}{5}\)

Step-by-step Solution

Detailed explanation

Let winning probability of C be P(C) = p \(\begin{aligned} & \therefore \quad P(A)=P(B)=2 p \\ & \because \quad P(A)+P(B)+P(C)=1 \\ & 2 p+2 p+p=1 \\ & \Rightarrow \quad 5 p=1 \\ & p=1 / 5 \\ & \end{aligned}\) \(\therefore\) Probability that \(B\) or \(C\) win \(=P(B)+P(C)\)…