AP EAMCET · PHYSICS · Mechanical Properties of Solids
The energy stored in a strained wire is given by
- A \(\frac{1}{2} \times\) load \(\times\) extension
- B \(\frac{1}{2} \times\) extension \(\times\) stress
- C \(\frac{1}{2} \times\) stress \(\times\) strain
- D \(\frac{1}{2} \times\) strain \(\times\) load
Answer & Solution
Correct Answer
(A) \(\frac{1}{2} \times\) load \(\times\) extension
Step-by-step Solution
Detailed explanation
Energy stored in a strained wire is equal to work done by the load to increase the length of wire. \(\therefore\) Energy, \(U=\) Work done \(=\) Average force (load)\(\times\) Extension in the wire \(=\left(\frac{0+F}{2}\right) \times\) Extension \(=\frac{F}{2} \times\)…
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