AP EAMCET · PHYSICS · Electromagnetic Induction
A rectangular loop circuit has a sliding wire \(P Q\) as shown in the figure. The loop is placed in a magnetic field \(B\), perpendicular to its plane. The resistance of the wire \(P Q\) is \(R\). If the wire moves with constant velocity \(v\), then find the current flowing in the wire \(P Q\) ?
- A \(\frac{B l V}{3 R}\)
- B \(\frac{B l v}{2 R}\)
- C \(\frac{3 B l v}{2 R}\)
- D \(\frac{2 B l v}{3 R}\)
Answer & Solution
Correct Answer
(D) \(\frac{2 B l v}{3 R}\)
Step-by-step Solution
Detailed explanation
Given, \(P Q\) arm is moving with constant speed \(v\) perpendicular to the magnetic field \(B\). Here, both resistances are in parallel, so their equivalent resistance, \(R^{\prime}=\frac{R \times R}{R+R}=\frac{R}{2}\) Now, the circuit becomes as shown in Fig. (b). Length of…
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